Java program to check whether the given number is even or odd
A number is said to be even if it is divisible by 2. otherwise odd.
Let us now see an example of a java program to determine whether the given number is an odd or even number.
Algorithm:
Step 1: Start.
Step 2: Read n.
Step 3: if n%2 == 0, then print n is even.
Step 4: else print n is odd.
Step 5: Stop.
Source code:
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import java.util.Scanner; class Even { public static void main(String args[]) { System.out.println("\n \n *** www.programmingposts.com *** \n \n"); System.out.println("<<JAVA Program to check whether the given number is even or not>>\n\n"); Scanner scanner = new Scanner(System.in); System.out.println("Enter number:"); int num = scanner.nextInt(); if(num%2 == 0) { System.out.println(+ num + " is even"); } else { System.out.println(+ num + " is odd"); } } } |
Explanation:
In the program, integer entered by the user is stored in variable num.
Then, whether the number is perfectly divisible by 2 or not is checked using modulus operator.
If the number is perfectly divisible by 2, test expression num%2 == 0 evaluates to 1 (true) and the number is even.
However, if the test expression evaluates to 0 (false), the number is odd.
Output:
C:\Users\santo\Desktop\new>javac Even.java
C:\Users\santo\Desktop\new>java Even
*** www.programmingposts.com ***
<< JAVA Program to check whether the given number is even or not >>
Enter number:
9
9 is odd
Screenshot of output:
